Explain Hardy Weinberg Theorem

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Explain Hardy Weinberg Theorem

 Explain Hardy Weinberg Theorem

Long Note for Class 12 Biology (Chapter 24 Evolution – 5–8 Marks Question) (RTS/HED/Punjab Board Pattern)

hardy weinberg theorm

Definition / Statement

The Hardy-Weinberg theorem (1908) states that: In a large, randomly mating population, the allele frequencies and genotype frequencies remain constant from generation to generation provided no evolutionary forces (mutation, natural selection, genetic drift, gene flow or migration) act on the population.

This is also called Hardy-Weinberg equilibrium. It describes a non-evolving population.

Hardy-Weinberg Equation

Let:

  • p p = frequency of dominant allele (A)
  • q q = frequency of recessive allele (a)

Then: p+q=1 p + q = 1 (allele frequency equation)

Genotype frequencies in the population: p2+2pq+q2=1 p^2 + 2pq + q^2 = 1

Where:

  • p2 p^2 = frequency of homozygous dominant (AA)
  • 2pq 2pq = frequency of heterozygous (Aa)
  • q2 q^2 = frequency of homozygous recessive (aa)

Assumptions (Conditions) for Hardy-Weinberg Equilibrium

For gene frequencies to remain constant, the following five conditions must be met:

No.ConditionExplanation
1Large population sizePrevents random fluctuations (genetic drift)
2Random matingNo preference for any genotype
3No mutationNo new alleles introduced
4No natural selectionAll genotypes have equal survival & reproduction
5No gene flow (migration)No alleles enter or leave the population

If any one condition is violated, the population evolves (gene frequency changes).

Significance / Importance

  • Acts as a null hypothesis (baseline) to detect whether evolution is occurring.
  • Helps calculate allele and genotype frequencies in a population.
  • Used in population genetics and to study genetic disorders.
  • Explains why recessive alleles are not eliminated from the population.

Example (Simple Calculation)

In a population, frequency of recessive allele (q) = 0.3 Then p = 1 – 0.3 = 0.7

Genotype frequencies:

  • AA = p2 p^2 = 0.49
  • Aa = 2pq 2pq = 0.42
  • aa = q2 q^2 = 0.09

Key Exam Lines:

  • “Hardy-Weinberg principle states that allele frequencies remain constant in the absence of evolutionary forces.”
  • “The equation is p2+2pq+q2=1 p^2 + 2pq + q^2 = 1 .”
  • “It is used as a mathematical model to measure evolution.”

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